![]() ∴ Graphs G1 and G2 are not an isomorphism. If the right angled triangle t, with sides of length a and b and. So because of the violation of condition 4, these graphs will not be an isomorphism. What changes is the depth of the tree, min depth 3. ![]() Since, Graphs G1 and G2 violate condition 4. Graph G2 is not forming a cycle of length 4 with the help of vertices because vertices are not adjacent.īoth the graphs G1 and G2 do not form the same cycle with the same length.Graph G1 forms a cycle of length 4 with the help of degree 3 vertices.There are an equal number of degree sequences in both graphs G1 and G2. If the first graph is forming a cycle of length k with the help of vertices.There will be an equal amount of degree sequence in the given graphs.There will be an equal number of edges in the given graphs.There will be an equal number of vertices in the given graphs.Hence, we can say that these graphs are isomorphism graphs.Īny two graphs will be known as isomorphism if they satisfy the following four conditions:.The same graph is represented in more than one form.The above graph contains the following things: The example of an isomorphism graph is described as follows: These types of graphs are known as isomorphism graphs. ![]() That means two different graphs can have the same number of edges, vertices, and same edges connectivity. The isomorphism graph can be described as a graph in which a single graph can have more than one form. Next → ← prev Graph isomorphism in Discrete Mathematics ![]()
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